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The product of two consecutive odd numbers is 399. What are the two numbers?

PLEASE DON'T TELL ME THE ANSWER. TELL ME HOW TO SOLVE IT. I WANT TO LEARN TO DO IT MYSELF. THANKS!!!

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32. If the product of two consecutive odd numbers is 399, the two numbers are 21 and 19. The equation to be formed to get the answer is x(x+2) =399. Therefore x^2 + 2x = 399 Complete the square by adding 1 at both sides ;
x^2 + 2x + 1 = 399 + 1 Use the formula: (a + b)^2 = a^2 + 2ab + b^2
(x + 1)^2 = 400
x + 1 = (+ & - )(square root of 400) subtract 1 to both sides
x = -1 (+ & -) 20
x = -1 + 20 or x = -1 - 20
x = 19 or x = -21
So,
x + 2 = 19 + 2 = 21 or x + 2 = - 21 + 2 = - 19
Thus the numbers are:
19 and 21 or -19 and - 21
Check:
(19)(21) = 399
(-19)(-21) = 399

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Im not sure the real mathy mc math math way, but i look at the number and i see its prett much 400, because the numbers are consecutive they will be almost the same so its a matter of __x__=400 then switch the numbers by one so they are consecutive odd numbers and BANG 399 is whatcha get

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Mathy McMath Math way... I love it, lol. Sounds like something I'd say.
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Lol thank you
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Hey neighbor remeber me the kid on your lawn lol wheres my sugar lol
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Hey wippersnapper! No sugar for you!!!
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Extremely hard to explain but this is the formula to find it i recommend you ask the teacher to explain it in better detail.
x(x + 2) = 399
x^2 + 2x = 399 Complete the square by adding 1 at both sides ;
x^2 + 2x + 1 = 399 + 1 Use the formula: (a + b)^2 = a^2 + 2ab + b^2

this is the mathy mc math math way