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What are the determined values of X in the expression: [squareroot( 5- X)]

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Determined values of x in the equation would be 5. This is calculated by separating the values in the brackets; ? 5 -? x. This is equivalent to 5^1/2 and x^1/2. Equating the two values 5^1/2 = x^1/2 and squaring both to get linear equations; (5^1/2)? = (x^1/2)?. Therefore, x =5 or x =0.

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You cannot have a square root of a negative number. This would be the case if: x > 5
The determined value is therefore anything above below 5. The is answer is: x < 5

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