The common factor in the equation is x, which means we'll try and have the x outside on a bracket. Since the common factor is x, we'll have x (3x3 + 15y - 27y3). In the same equation, another factor of x can emerge, which is 3x (x3 + 5y - 9y3).
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Last edited at 2:57PM on 6/3/2012
What is the common factor in the 3 terms of the equation (factor found in the 3 terms) --> it is (x). So if we took x outside, the equation will be; x (3x^3 + 15y - 27y^3) There is another common factor, which is 3; 3x (x^3 + 5y - 9y^3)