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ghanti: 11 months ago

Sum of two natural numbers is 21 and their difference is 11, find the numbers.

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Answer 1

okenuson: 11 months ago

the numbers are x=16,y=5.
x+y=21....(1)
x-y=11....(2)
solving (1)and (2) simultaneously by elimination method.
eliminating x:
equation(1) - equation(2)
2y=10
y=10/2
y=5
substitute y=5 into equation (1)
x+5=21
x=21-5
x=16.
therefore the numbers are 16 and 5 respectively.

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Answer 2

iAimtoPlz: 11 months ago via iPhone

16+5=21
16-5=11

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Answer 3

r0sesarered: 11 months ago

The two numbers are 5 and 16. To arrive to these answers, express the statement question in the form of expressions x+y=21 and x-y=11. Then do x=21-y so that you get the value of x. substitute this value of x in the second expression in order to give you (21-y)-y=11, which then gives 21-2y=11. So 2y=21-11, which gives 2y=10 hence y=5. Then substitute they value of y in the first expression x+y=21 to get the real value of x, x+5=21. So x=21-5=16, therefore, x=16.

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Answer 4