Submit a question to our community and get an answer from real people.

A ball is tossed 80m above the ground with a velocity of 40m/s due east. What is the ball's velocity after 3 second?

Free random motion

Report as

no loss from air resistance?
find the vertical component of the velocity:
v = at
you know the horizontal, it's still 40m/s

Report as

Given that the ball is tossed 80m above the ground with a velocity of 40m/s due east, the ball's velocity will be 69.4m/s after 3 seconds. Use the formula v=v0+at.

Report as
Report as

Neglecting friction, the horizontal component remains unchanged. The vertical component is vz=gt=-10 m/s^2 * 3 s = 30 m/s. The velocity is therefore (40 m/s, 0, -30 m/s) where the x component is in the east direction, y component in the north direction, and z component pointing up. The speed is the magnitude of this vector, and is given by v=sqrt((40)^2+(30)^2) m/s = 50 m/s (you were not asked about the speed. Your final answer is the vector whose components are written above.)