What is the solution of "The perimeter of an isosceles triangle is x^3+y^3-z^3. Its unequal side is 3/4 of x^3-4y^3+z^3.Find the other side.
Umm I don't know. I'm not to good with English.
1/8 times x^3+y^3-z^3 is the the two identical sides, 1/8th + 1/8th + 3/4 = 1 the perimeter is only one x^3+y^3-z^3
Well if it's an isosceles then wouldn't it be the same, (x3+y3-z3)?
I HOPE you mean find the other 2 sides. Each one is (1/8)x^3 + 2y^3 - z^3. I took the Perimeter, subtracted the 3rd side and divided result by 2.WHO IS RIGHT??!!!!!!!!???