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ana(n1)=b(n1)=?
b2b1=c1=1
.........
b(n1)b(n2)=c(n2)=?
c2c1=1
c3c2=2
c4c3=3
.........
c(n2)c(n3)=n3
c(n2)c1=(n2)(n3)/2
c(n2)=1/2n²5/2n+4,
b(n1)b1=1/2(3²+4²+...+n²)5/2(3+...+n)+4(n2)
=1/12n(n+1)(2n+1)5/25/2(1+n)n/2+15/2+4(n2)
b(n1)=1/6n³1/6n²1/6n4(n1)=1/6n³n²+17/6n2
ana1=1/6(1+2³+...+n³)1/6(1+2²+3²+..+n²)+1+17/6(1+...+n)17/62(n1)
=1/6(1/2n(n+1))²1/6n?n+1)(2n+1)+17/12n(n+1)2n
an=1/24n^41/4n^3+23/24*n^23/4n+1;
I major in Mathematics,and I happen to know the answer.