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Ok math question for non idiots unlike yous truly solve the system of equations: y=-x-2
and 5x-3y=22 oh and how?

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If y = -x-2 substitute that where you see y in the equation
5x-3y = 22
5x-3 (-x-2) = 22 now multiply -3 (-x-3)
8x+6=22 get you whole numbers on on side by subtracting 6 on both sides
8x=16 divide both sides by 8
x=2
Since you now now x=2 you can solve for y
y= -2-2
y=-4
5(2) -3(-4)=22
10+12=22

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thanks its so ironic its the only class i need to graduate and i suck at it and am failing
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You are probably overthinking it. Just break everything down and work one step at a time.
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Homework probably
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PS what grade are you in?
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cause im an idiot and cant figure it out senior in highschool btw
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Oh... Im 13... I cant help you there... I dont know what that stuff means... sorry :(
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Don't you graph the points?

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no you have to solve the system
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x= -3 and y= 1. how to do this equation is simple but has alottta steps and i dont feel like typing all of them haha

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to bad my teacher wants me to show my work
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oops got the answer wrong haha wait
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x= 8 and y= -10 and the work is: on y=-x-2 you add x to the side with y to make it x+y=-2 then u multiply the whole thing by 3 to make it 3x+3y= -6 then u put it under 5x-3y=22 and subtract it giving you 2x= 16 then x= 8. then u plug x=8 into y=-x -2 giving u y= -8 -2 and then it equals y= -10
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1=1-2and i dont know the last one sorry :-)

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