Submit a question to our community and get an answer from real people.

A right triangle has a perimeter of 4 feet and one side is 2 feet less then one of the sides. What are the lengths of the sides?

Report as

There is no answer to this question. That triangle cannot exist.

Keep in mind the rule that triangles must follow - any two of the sides must always add up to a number greater than the length of the third side.
For example, if you had a triangle with sides of lengths 3, 4 and 5: 3 and 5 added is 8, which is greater than 4; 3 and 4 added is 7, which is greater than 5, etc.

In this question, we have a triangle with a perimeter of 4 and one side is 2 feet shorter than another. Let's make up side lengths in order to prove that this is not a real triangle; I'll say that one of the sides is
2.1 ft, and the one that is 2 feet shorter will be 0.1 ft.

Those two sides add up to a total length of 2.2 ft. With a perimeter of 4 ft, that means that the remaining side must be 1.8 ft. Now let's test it.
If we add the shorter sides (0.1 ft and 1.8 ft), we will have a length of
1.9 ft...which is not greater than 2.1 ft. Therefore, this triangle is not a real triangle.

Report as

you mean right ANGLE? then one is 3 and another is 1 but what is right triangle?i know equaliteral triangle scalene triangle and isosceles triangle

Report as
The angle sides are infinite... He meant a triangle which has a right angle.

@Metto: a+b+c=4, a=b-2 (or a=c-2) and you can use Pythagorean Theory.
Report as
I'm pretty sure you have to do it with the sides being x, x+2, 4-x-(x+2) and then using Pythagorean Theorem but I still can't find the answer.
Report as