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How to factor the trinomial 2x^3-8x^2+8x. Please I really need help

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they all have an x so now your left with 2x^2-8x+8 multiply 2 times 8 you get 16 factor of 16 that equals 8 is 4 and 4 now you have (2x^2-4x) (4x+8) you cab put these in a punnet square and you will end up with (2x+4) and (x+2) thid is how I learned when I was a junior in highschool.hope I helped:)

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Factor out 2x first.
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oops my bad yes thank you for correcting me:) 2x so that leaves you with x^2-4x+4. then you get 4 multiples of 4 are 2*2 so now you have (x^2-2x) (2x+4) then in your punnet square you would get. (x+2) (x+2) this is the answer:)
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pie

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2x^3 - 8x^2 + 8x =
2x(x^2 - 4x + 4). =
2x(x - 2)(x - 2). ANSWER

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2x(x-2)(x-2) or 2x(x-2)^2
Since you use FOIL (first, outer, inner, last)
First: x*x= x^2
Outer: x*-2=-2x
Inner: -2*x= -2x
Last: -2*-2=4
Add them to get x^2-4x+4
Then multiply each term by 2x.
That is how you know the answer is right.