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How to find x on an isosceles triangle?

I'm given two angles, one angle is (20x-10) and another angle is (9x+4). what is x and how did you get it

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(20x -10)+(20x-10)+(9x+4)=180.

Proper equation, since two of the angles must be the same. In order to get an isosceles triangle. After all the algebra.

X=4.

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Thank you
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So by using the triangle angle sum theorem, you should know that all the angles should add up to 180 degrees. Sooo your equation would look like this:
(20x+10) + (9x+4) = 180
Subtract 10 from each side
x+9x+4 = 170
Subtract 4
20x+9x = 166
29x = 166
Divided by 29

Then you have to plug it in to the equation to find the angles.
20(5.742) - 10 = 104. 84

9(5.742) +4 = 55.678

104.84 + 55.678 = 160.518
180 - 160.518 = 19.482
That's the last angle.

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Very wrong...
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I don't even understand how you did what you just did. Your triangle only has two angles and the plus ten randomly turned into minus ten. I'm sorry but no.
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