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There are 3 doors, 1 of them has a million\$ behind it. You choose one at random. Another of the 3 doors opens to reveal nothing.

Are you more likely to get the million\$, opening your chosen door, or the other unopened one?

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Well, statistically, it is more likley that the remaining one that you did not choose has the million. It goes like this:
When you first chose either door number 1, 2, or 3, there was a 33.33333...% chance that you had chosen correctly. Lets say that you chose #3. Then it would be revealed that one of the other ones (lets say #1) did not have the million behind it. Now, since #1 is removed from the equation, many would think that you then had a 50/50 chance of having picked the right one in the first place. In all actuality, it would be better to change to the #2 door because that door now has a 66.66...% chance of having the money as apposed to your origional choice that still has a 33.33...% chance of having the money. YAY MATH! haha

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It seems like you're the first one to actually understand the question.
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I think so :) I love riddles
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I'm not sure if this could be considered a riddle.
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Yeah, I guess not... then I guess I could say I like fun math. The operative word beind fun.
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*being
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Wow, replying to something I said 3 months ago?
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The million, I'm lucky!!

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What?
Your choices are "the one I chose" and "the other one".
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the unopend one??????

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Yes.
Mathematically, you have twice the chance if you pick the unchosen, unopened one.
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Does the third one kill me?

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what's behind door #3

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