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I have a triangle with a hypotenuse of 17, a short leg of 8 and long leg of 15.

What is sin x- cos x if x is the angle opposite of the short leg? Please explain, I am so confused!

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Oooh AP geometry... dont look at me lol I barely passed REGULAR geometry.

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8)
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divide the adjacent side by the hypotenuse (adjacent is connected to the angle your using, hypotenuse is longest line) so it's 17/8 (if 15 is THE angle)=8.61
or if 8 is the angle your using: 17/15=1.13 Then take SIN (opposite/hypotenuse)which is 8/17= 0.47 or 15/17=.88
SIN- COS= (I don't know which numbers you need, just plug them in from above)

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Thank you! I don't really know what sin,cos, and tan is used for so this makes it easier.
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the opposite of the angle is the sin always so the sin of x sin x= 8/17 the cos x, being the adjacent/hypotenuse is 15/17 and the tan x= 8/15. the sin is basically the short leg of a triangle usually over the hypotenuse of a triangle, however, if the angle x happens to have the adjacent side as its opposite then the sin x would change to adjacent/hypotenuse only in that case. it depends where the angle x or theta, beta, etc falls. its opposite is usually what number you use over the hypotenuse to answer your question. however if the angle falls on the hypotenuse which it almost never will you just use the short leg over the hypotenuse itself never the hypotenuse over anything.

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