Can you help me for my math problem? It's confusing me!! Solve the following system of equations.d + e = 6d - e = 4
So...to solve it: You can Add the columns D+e+(D-e)=6+4So: 2D=10or D=5Plug that in to either equationD+e=65+e=6e=6-5e=1Therefore: D=5 and E=1
It looked different on the q & a page, sorry i thought it was one whole problem
do you mean d+e=6d and then -e=4 ??
D=5 e=1. 5+1=6. 5-1=4
If d + e = 6 then d = 6 - e ( - e from both sides of first equation)Now just substitute d in the second equation with this: 6 - e (6 - e) - e = 4