A car accelerates from rest at a constant rate of 2.1m/s squared for 7.0 seconds . How far does the car travel in this time?
X = X(0) + v(0)t +(1/2)at^2X(0)=0V(0)=0So X = (1/2)at^2 Where a is acceleration and t is time.
Distance = rate x timeD = 2.1 x 7D = 14.7 mi. ANSWER