1) Put it in slope-intercept form: y = mx + b 3x + 5y = -5 -3x. -3x 5y = -3x - 5 /5. /5 y = (-3/5)x - 1 2) Graph Put a point on (0, -1) on y-axis From that point move down 3 and right 5. Put a point on (5, -4). 3) Draw a line through the 2 points and label it y = (-3/5)x - 1.
To graph the equation, solve to find the value of y. Use one of the arbitrary values of x. This will give you the equation in the form of y = mx + c. Plot a line on the graph using this solution. Solve for y using the other arbitrary values of x. Plot the point and then connect the two dots. The point they meet on the graph is the solution for x. Visit http://www.wtamu.edu/academic/anns/mps/math/mathlab/int_algebra/int_alg_tut12_graph.htm for more information.
Well first you subtract 3x to the other side ... So it's 5y= -3x-5 then you divide by 5 : y= -3/5x-1 then you find -1 on the y axis (plot the point) and then go down 3 then over to the right 5 (plot the point) then down 3 over the right 5.