The diagonal of a square has a length of 8 times the square root of 2 cm. Find the length of a side of the square.
Let s = side of the squares^2 + s^2 = diagonal^2 by the Pythagorean Theorem2s^2 = (8sqrt 2)^22s^2 = 64 x 22s^2 = 128s^2 = 64sqrt s^2 = sqrt 64s = 8. ANSWER
8 its just that simple