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How Much Would 3 Computers, 4 Printers, 15 DVDS, And 18 Cds Cost?.

A.432 B.324 C.234 D.6818 E. 3168

PAUL Purchased 8 Computers Which Cost Him A Total Of \$6,016 And MARY Purchased 8 Printers Which Cost Her \$1,080. STEVE Purchased 25 DVD Movies Which Cost \$350 And SALLY Purchased 34 Cd's Which Cost \$306.

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8 computers cost \$6016 --> 1 computer costs (\$6016 / 8) = \$752
8 Printers cost \$1080 --> 1 printer costs (\$1080 / 8) = \$135
25 DVDs cost \$350 --> 1 DVD costs (\$350 / 25) = \$14
34 CDs cost \$306 --> 1 CD costs (\$306 / 34) = \$9
So 3 computers, 4 printers, 15 DVDs and 18 CDs will cost [(\$752 x 3) + (\$135 x 4) + (\$14 x 15) + (\$9 x 18)] = \$2256 + \$540 + \$210 + \$162

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I Got Letter E. For This Question. I Just Want A Second Opinion If My Answer Is Correct.
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Three computers would cost \$2256, 4 printers would cost \$540, 15 DVDs would cost \$210 and 18 CDs would cost \$ 162. To get this answer, you will have to divide the amount of money used by Paul, Mary, Steve and sally. From the division, you will get the price of each computer, printer and the rest.