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How would you solve this math problem?

The product of two consecutive numbers is 14 less than 10 times the smaller number. Find each number.
Please help! it would be nice if you would show your work! Thanks

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To make it easier let just convert what you said into equations;
Let the two consecutive numbers to be (x) and (x+1), then;
(x) (x+1) = 10x - 14
x^2 + x = 10x - 14
x^2 - 9x + 14 = 0
(x - 7) (x - 2) = 0
x = 7 0r x = 2
then the two numbers would be (7 and 8) or (2 and 3)
I hope you got it from me :)
Try to repeat it again and try the solution with question head and see if it will satisfy it or not.
Good Luck :)

Helpful (1) Fun (1) Thanks for voting Comments (3)
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Thanks :)
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Star for you
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You are welcome..thank you :)
I just hope you understood it...
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