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What's the difference between 64bit and 32bit?

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Shave and Haircut . . . 2-Bits.
A Spanish Dollar "Piece of Eight" can be broken into 8-Parts.

Computers use an 8-Bit Character identification (A,B,C, 1, 2, 3, a,b,c, #, *, \$, etc.)
for a Total of 256-Characters.

Old personal computers are 4-Bit systems.
- Meaning it takes 2-Instructions to transfer One-Character.!
New personal computers are 64-Bit systems.
- Meaning it takes 1-Instruction to transfer 8-Chacters.!

As 32-Bit systems takes 1-Instruction to transfer 4-Chacters.!
Next will be 128-Bit systems and 256-Bit systems.

ALL depends on how powerful the CPU can be designed.!
Small-Personal computers can -not- compete with Main-Frame computers.!
However . . . You can -not- place a Main-Frame computer in a Satellite.!

Computers are only as smart as a "Light Bulb".
Meaning 1-Bit can be turned OFF -or- ON . . . Binary Numeric System.

Example: a dot will mean OFF and a 1 will mean ON.
.... .... is zero - .... ...1 is one - .... ..1. is two - .... ..11 is three - .... .1.. is four
note each position is Binary vs Decimial by 10.
1, 2, 4, 8, 16, 32, 64, 128, 256, 512, 1024, etc. - 1111 1111 is 255 plus zero = 256

Class dismissed. Good by

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except binary is zero and ones not dots 0101001001 is a binaey not ...1..1.1
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Note-2: See a space for Readability between High-order and Low-order.
- High-order contains the Sign
- Low-order contains the Digit

Note-3: Conversion of Binary to Hexadecimal
- Value 0-9 use characters 0-9
- Value 10 use character A, 11 is B, 12 is C, 13 is D, 14 is E, 15 is F
- Example Binary 1111 1111 is Hexadecimal FF is 255
- When you 'Dump' a program, it will display in Hexadecimal.

- Everyone else only cares How the Program runs.!
- Sometimes Programers Lock a Back-Door with Special Key-Sequences
- - to Bypass Program Rules.!

Good-Bye
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all I am saying is in all the many many years I have worked with computers I have never seen or heard binary stated with dots it is always in ones and zeros!! ans as most people don't know all the technical terms using the ones and zeros to explain binary is easier to understand than dots. relize that most people don't have the extensive education of how binary code works and describing it as easily as possible and how most everyone knows binary as is simplist. I never hears of using dots instead of zeros yntill you said this. in a numeric system with character from 0 thru 9 how do you show a dot anyway? just asking because 0 1 2 3 4 5 6 7 8 9 has no dot as a character.
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Please do -not- get too involved with Binary.
It was just used to answer Main Question.

You can use Comma for OFF and k for ON.

My computer education began in 1968.
- Univac 9300, 16Kb memory, upgraded to 24Kb memory.

As you know, computers really use Hexadecimal.
Above Note-3 explains conversion to Hexadecimal.

Hex C1 -> C9 are display characters A - I
Hex D1 -> D9 are display characters J - R
Hex E2 -> E9 are display characters S - Z
Hex F0 -> F9 are display characters 0 - 9

kk,, ,,,k -> kk,, k,,k in Binary
kk,k ,,,k -> kk,k k,,k in Binary
kkk, ,,k, -> kkk, k,,k in Binary
kkkk ,,,, -> kkkk k,,k in Binary

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U just copied and pasted something from the dictionary
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But thanks!
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Thank you.! I wrote the dictionary.!
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its an operating system, 64bit is the better choice

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64 bit is not an operating system... -.-
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SO much fail...
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32 bit is less than 64 bit because 64 > 32.

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you dont say
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When computers need to address memory or commands they have a determined "word" size. That word can be made of of various numbers of "bits" The larger the number, the bigger the "address" space is and the more information that each "word" can carry. The world of computers is binary, and everything is by factors of 2. The next step of from a 32 bit word is a 64 bit word. A byte is defined as 8 bits, so a 64 bit word can hold 8 bytes and a 32 bit word can hold 4 bytes. The biggest factor in this is the concept of "address space." And a 64 bit address space is huge in comparison to a 32 bit address space.

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The main differences between the 32-bit versions of Windows Vista and the 64-bit versions of Windows Vista relate to memory accessibility, memory management, and enhanced security features. The security features that are available in the 64-bit versions of Windows Vista include the following:
Kernel Patch Protection
Support for hardware-backed Data Execution Protection (DEP)
Mandatory driver signing
Removal of support for 32-bit drivers
Removal of the 16-bit subsystem
One of the greatest advantages of using a 64-bit version of Windows Vista is the ability to access physical memory (RAM) that is above the 4-gigabyte (GB) range. This physical memory is not addressable by 32-bit versions of Windows Vista.

Depending on the version of Windows Vista that is installed, a 64-bit version of Windows Vista supports from 1 GB of RAM to more than 128 GB of RAM. The ability to address more physical memory lets Windows Vista minimize the time that is required to swap processes in and out of physical memory. Therefore, Windows Vista can manage processes more efficiently. This memory management feature helps improve the overall performance of Windows Vista.

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Simple. 64-bit is better than 32-bit.

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It can also be the quality of a program or file. I save my music I make in 64-bit even though I have a 32-bit computer. It takes FOREVER but the quality is impeccable. The next step up, 80-something bit, is too much for my computer.

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Also 64bit windows supports hard drives over 2TB

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32

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In short, the 64-bit version of Windows handles large amounts of random access memory (RAM) more effectively than a 32-bit system.

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The main differences between the 32-bit versions of Windows Vista and the 64-bit versions of Windows Vista relate to memory accessibility, memory management, and enhanced security features. The security features that are available in the 64-bit versions of Windows Vista include the following:
Kernel Patch Protection
Support for hardware-backed Data Execution Protection (DEP)
Mandatory driver signing
Removal of support for 32-bit drivers
Removal of the 16-bit subsystem
One of the greatest advantages of using a 64-bit version of Windows Vista is the ability to access physical memory (RAM) that is above the 4-gigabyte (GB) range. This physical memory is not addressable by 32-bit versions of Windows Vista.

Depending on the version of Windows Vista that is installed, a 64-bit version of Windows Vista supports from 1 GB of RAM to more than 128 GB of RAM. The ability to address more physical memory lets Windows Vista minimize the time that is required to swap processes in and out of physical memory. Therefore, Windows Vista can manage processes more efficiently. This memory management feature helps improve the overall performance of Windows Vista