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If an olympic cyclist reaches 18m/s from a standing start in 20s, what is her average acceleration?

This is for physics. I haven't had my first official day for it so I'd like to get ahead a bit. I would like to know the formula used to solve this problem and an explanation for the phenomenon concerning it.

The answer should be 0.90 m/s squared (If possible, I'd like to know why it is squared...)

- sincerely, a confused student.

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v = u + a(t)

Where v = Final Velocity,
u = Initial velocity,
a = acceleration,
t = time taken,
s = distance traveled.

(18 meters / second)^2 = (0 meters /second)^2 + a *(20 seconds)

When you solve this equation, including operating on the units according to the same rules for multiplying the numbers, you will come up with a number that has sec^2 as the unit.

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Thank you very much!
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You're quite welcome.

Getting ahead is a great idea. I suggest you "pre-scan" the next topic; but if it doesn't make sense to you, wait for the lecture.

Best of luck in your studies.
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