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I need help with algebra?

Just a little header on solving an i equality. I can solve an equation easily like 1+x = 6 etc. but what's the difference in the operation when solving an inequality for example 2y + 1 > 5y - 8

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It's very easy. You add/subtract the "y" number to one side and you do the same for the regular number. I'll answer it in the comments considering I've already forgotten what the problem was

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Y=3
Easy enough? If u don't get it please tell me what you're finding hard about it.
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I tried that, am i doing it right?

2y+1 > 5y-8
-1 -1
2y > 5y -9
-5y -5y
-3y > -9

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Yup that's one of two ways to answer it. You could have moved the y first as well. Either way your answer comes out the same. Sorry for the wait I had a busy schoolday
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Ok so I get y>3 but how does that solve for the variable? Am I supposed to just write y>3? Or is there a way to know exactly what y is? The question said solve for the variable
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Nvm I checked the answer sheet and it really was y>3 thanks
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