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How do you factor (x-y)²-(x+y)²? Please help.

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we know a^2-b^2=(a+b)(a-b) so
(x-y)^2-(x+y)^2=[(x-y)+(x+y)][(x-y)-(x+y)]
=(x-y+x+y)(x-y-x-y)
=(2x)(-2y)
=-4xy

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Is this a perfect square?
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no its not a perfect square
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Ohh ok no I get it. Thanks can you explain like 5 more? I didn't understand these 6 problems
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I think its 2x-2y-2x+2y. you times each letter by the exponent which in this case is "2".

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See the answer is suppose to be -4xy
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oh sorry I thought you just meant what does it look like after you just times each by two.
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-4xy

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I know that too but how did you get there?
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(x-y)(x-y) - (x+y)(x+y) = x^2-2xy+y^2-x^2-2xy-y^2 = -4xy
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