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I have some math work but i am so confused on how to do it and if i fail my test, im in huge trouble. Here is what i need help with (Solving) Could you please either answer these questions or give me a simple way to answer them? thanks soooo much
Lesson: Solve Equations with variables on each side

2x + 6=x + 15
3x - 2=8x - 32
-12 - x=8 - 3x
6x - 15=65 + x
x/2 - 12= -3 + x (x over two)
13x + 8= 65 + 10x
4x - 31=11 - 2x
26 - 2x=2x + 2
8 - x=x + 36
x/4 - 3= x + 8 (x over four)
9x - 4=32 + 5x

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1. Find the variable with the smallest amount. I'll use the first problem as an example.
* 2x + 6 = x + 15 "x" on the right side is the smallest because there is only ONE x.

2. If the variable has a positive number, subtract. If the variable has a negative number, add.
* I know that the single "x" doesn't have a number in front of it, but there is actually an invisible 1 in front. Since the 1 is positive, you subtract "1x" from both sides. That would leave you with x + 6 = 15.

3. Now that you've finished with the variables, do the same with the normal numbers. Add/subtract the number on the same side as the variable.
* Subtract 6 from 15, leaving you with x = 9.

I'll do the second problem as a refresher.

3x - 2 = 8x - 32
-3x -3x
-2 + 5x - 32
+2 +2
5x = -30 *If you get into this situation, divide the non-variable number by the coefficient
/5 /5
x = -6

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thx a lot
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Omg. So glad that part of my life is over
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yea ur the lucky one
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no problem LOL
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