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Need help with this algebra equation 16x-15-9x=13

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16x - 15 - 9x =13
16x - 9x = 13 + 15
(16 - 9)x = 28
7x = 28
x = 28/7 = 4
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19x-15=13

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Add 15 to 13 then you subtract 9x from 16x and you will have 7x= 28 then you proceed to take 28 and devide by 7 therefore, x=4 ^-^

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variables on one side, like number on the other so add 15 to both sides which equals 16x-9x=28 then solve 16x-9x which is 7x so 7x=28 now divide each side to get x alone and the answer is x=4

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I'll give the same answer, hopefully in a little more understandable form. You want to end up with an equation that has x on one side and a number on the other. So, first get rid of the extraneous numbers by adding 15 to each side, 15 + -15 = 0, so now you have 16x - 9x = 28. Subtract the 9x from the 16x to get 7x = 28. To get x by itself you divide both sides by 7 to get 7x / 7 = 28 /7 or x = 4.

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