Submit a question to our community and get an answer from real people.

Why do they tell us that there are prime numbers when all numbers have square roots? doesn't that make that false?

Report as

I do not know what you are trying to say. A prime # is a # that can only be dived by 1 & it's self.

The square root of a # is when two # times each other = the # that you want . Example the square root of 25 is 5 becuse 5 X 5 =25

Report as
but since every number has a square root, a prime number can be divided by more than just one and itself, meaning that it isn't prime at all.
Report as
It may be divisible by more than 1 and itself, but it can't have a number divide into it EVENLY.

Example: 7

Divisors 1 and 7.

Square root: 2.64575131106 {(Not even), E.g., "Prime"}

Example: 4

Divisors 1, 2, 4

Square root: 2 {(Even), ergo NOT "Prime".}

Report as
The square root if a prime # can not be a hole #
Report as

the prime numbers have to have square roots that are whole numbers greater than 1

Report as

Ikr also negative numbers don't have any and also they are talking about whole numbers

Report as
Negative numbers actually do have square roots. They're called "Imaginary Numbers":

http://en.wikipedia.org/wiki/Imaginary_number
Report as