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How to factor 2x^2+5x+3?

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2x^2+5x+3 = (x+1) (2x+3)
http://www.tutorvista.com/math/binomial-factors-of-polynomials?cpid=50707&sa=1
Explanation:
Given 2x^2+5x+3
Step 1 : 2x^2 + 2x + 3x + 3
Step 2 : (2x^2 + 2x) + (3x + 3)
Step 3 : 2x(x+1) + 3(x+1)
Step 4 : (x+1) (2x+3).

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that is hard to explain in words, but if you google an example of that, they will show you step by step

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Use two binomials which are 2 sets of 2 term equations like (2x+2) (3x-9) use FOIL method (first, inner, outer, last) in those binomials to get factoring straight make sure and guess and check no way to do it

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Factoring is kind of a like a guess-and-check or trial-and-error type of procedure. In your case, here's how to go about solving it.

Original function: 2x^2+5x+3. Since the first term is 2x^2, you know that the first terms of each factor are 2x and x. So now you need to figure out the constants, a and b, in (2x+a)(x+b). The product of a and b must be 3 to satisfy the function, so they must be 1 and 3. Now you need to arrange these numbers correctly to meet the requirement. The answer is (2x+3)(x+1).

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you factor it using a method called F.O.I.L.
what times what equals two x squared? and the answer is x times 2x
then ask what times what equals 3?
the answer is 1 times 3
now you should have (x+1) (2x+3) or (2x+1) (x+3)
to check to see which is right, you check the first and multiply x times 3 and multiply 1 times 2x. if you add the products, you get 5x which is the correct answer.