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How do i solve 3x+6y=24

how do i solve 3x+6y=24

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If you're solving for both x and y, you need to do two separate solutions, where you isolate each variable to find its value. The formula actually follows several steps:

To isolate x:

3x + 6y = 24
3x + 6y - 6y = 24 - 6y
3x = 24 - 6y
3x/3 = (24 - 6y)/3
x = 8 - 2y

To solve for y:

3x + 6y = 24
3x - 3x +6y = 24 - 3x
6y = 24 - 3x
6y/6 = (24 - 3x)/6
y = 4 - 1/2x

So there, you have the algebraic value of both x and y. To find the numerical value, you substitute one value for the value you're looking for into the original equation.

To find the numerical value of y, substitute x for (8 - 2y):

3x + 6y = 24
3(8 - 2y) + 6y = 24
24 - 6y + 6y = 24
24 - 24 +0y = 24 - 24
0y = 0

To find the numerical value of x, substitute y for (4 - 1/2x):

3x + 6y = 24
3x + 6(4 - 1/2x) = 24
3x + 24 - 3x = 24
3x -3x + 24 - 24 = 24 -24
0x = 0

That's what I got to the best of my ability, but I'd definitely double-check with your tutor because those answers are very awkward.

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To find X and Y you have to do two diff questions.

solve for X:

3x = 24
to get X by its self divide 24 by 3
and you sould get around 1.3
after rounding it sould be 1

solve for Y:

6y = 24
to get y by its self divide 24 by 6
and you sould get 4

check solution:

take your solution of x and y and put it back into the problem.
3(1.3) + 6(4)
and you sound end up getting 24.
then you have you answer

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Unfortunately that's not the way it works. You can't simply get rid of one variable while you're solving for another, because it changes the result you're going to get. In order to solve for individual variables you have to isolate one of them on one side of the equation.
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Add 6 and 3. subtract the answer from 24. You take it from there.

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X=8+2y then substitute

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