How do i solve 3x+6y=24
how do i solve 3x+6y=24
If you're solving for both x and y, you need to do two separate solutions, where you isolate each variable to find its value. The formula actually follows several steps:To isolate x:3x + 6y = 243x + 6y - 6y = 24 - 6y3x = 24 - 6y3x/3 = (24 - 6y)/3x = 8 - 2yTo solve for y:3x + 6y = 243x - 3x +6y = 24 - 3x6y = 24 - 3x6y/6 = (24 - 3x)/6y = 4 - 1/2xSo there, you have the algebraic value of both x and y. To find the numerical value, you substitute one value for the value you're looking for into the original equation.To find the numerical value of y, substitute x for (8 - 2y):3x + 6y = 243(8 - 2y) + 6y = 2424 - 6y + 6y = 2424 - 24 +0y = 24 - 240y = 0To find the numerical value of x, substitute y for (4 - 1/2x):3x + 6y = 243x + 6(4 - 1/2x) = 243x + 24 - 3x = 243x -3x + 24 - 24 = 24 -240x = 0That's what I got to the best of my ability, but I'd definitely double-check with your tutor because those answers are very awkward.
To find X and Y you have to do two diff questions.solve for X:3x = 24 to get X by its self divide 24 by 3 and you sould get around 1.3after rounding it sould be 1solve for Y: 6y = 24to get y by its self divide 24 by 6 and you sould get 4check solution: take your solution of x and y and put it back into the problem. 3(1.3) + 6(4)and you sound end up getting 24.then you have you answer
Add 6 and 3. subtract the answer from 24. You take it from there.
X=8+2y then substitute