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# How do you calculate antilog?

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Calculating the antilog of a number is the inverse of calculating the logarithm of a number. One is capable of determining the base "b" antilog of a number "x" by calculating the value b^x, or b to the power of x.

Common bases used when calculating antilog are base 10 and base e. For example, the base 10 antilog of the number 3 is equal to 10^3, or 10*10*10 = 1000. The base "e" antilog of the number 3 is equal to e^3, or approximately 20.0855. Some buttons or series of buttons on calculators that represent antilog include LOG-1, 10^x, ALOG and INV LOG. Also, the e^x button calculates the natural antilog. The antilog of a logarithm of a positive number "x" is equal to x, assuming that the antilog and log use the same base. For example, a base 10 antilog of "log 3" is equivalent to 10^(log 3), which equals 3.

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Q:
## What is the inverse function of "In"?

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Full Answer >**The inverse function of ln(x) is e^x, where e is the mathematical constant e = 2.718.**One can easily check that these two functions are inverses of each other by noting that ln(e^x) = e^ln(x) = 1.Filed Under: -
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## What is the opposite of an inverse relationship?

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Full Answer >**The opposite of an inverse relationship is a direct relationship.**Two or more physical quantities may have an inverse relationship or a direct relationship. Temperature and pressure have a direct relationship, whereas volume and pressure have an inverse relationship.Filed Under: -
Q:
## What formula do you use for the integral of inverse tangent?

A:The formula for the integral of inverse tangent is the integral of arctan(x) dx = x * arctan(x) - (1/2) * ln |x2+1|+ C. The integral is solved using integration by parts, which notes that the integral of u dv is equal to u times v minus the integral of v du. The term arctan represents the inverse function in mathematical formulas.

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## How do you calculate the midpoint Riemann sum?

A:A Riemann sum is a method of approximating the area under the curve of a function. It adds together a series of values taken at different points of that function and multiplies them by the intervals between points. The midpoint Riemann sum uses the x-value in the middle of each of the intervals.

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