A box has 5 red and 4 blue balls- in how many ways can 4 balls be chosen such that there are at most 3 balls of each color?

Answer

This is a combination problem because you have to assess a subgroup without a particular order. I find it easiest to first deduce what the total number of arrangements are and then subtract from there. Firstly, There are a total of 9 balls getting as

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