How much does a cubic foot of gold weigh?


A cubic foot of gold weighs approximately 1,206 pounds. A cubic inch of gold weighs approximately 0.7 pounds. Gold is a dense, heavy metal, and if a 1-gallon milk container was filled with gold, it would weigh about 161 pounds.

A standard bar of gold as held in the United States Mint measures 7 inches long by 3 5/8 inches wide by 1 3/4 inches tall and weighs approximately 400 ounces or 27.5 pounds. In the 21st century, the U.S. Mint held a maximum of 649.6 million ounces of gold in 1941. As of 2014, it had gold holdings of 147.3 million ounces, according to

Q&A Related to "How much does a cubic foot of gold weigh?"
Pure gold has a density of 19.32 grams per cubic centimeter. A cubic foot contains 28,316.85 cubic centimeters. Thus, a cubic foot of pure gold has a mass of 547,081 grams, which
Uranium weighs 53 802.015 grams per cubic foot. It is 1.9 grams per
Weight of Gold. Gold is weighed in ounces. A gold ring would be about three to seven ounces depending on the amount of actual gold in the ring, although individual rings could weigh
One cubic foot of gold weighs about 1204.8586 pounds (546.51424 kg) Or about 1/3rd of an average car! report this answer. Updated on Wednesday, February 01 2012 at 09:07AM EST. Source
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