Balanced Equation for Combustion of Butane?


Butane, C4H10, is a component of natural gas. C4H10 + O2 -> CO2 + H2O. Balancing the equation would result in the following 2C4H10 + 13O2 -> 8CO2 + 10H2O.
Q&A Related to "Balanced Equation for Combustion of Butane?"
There are two possible reactions involving the combustion of butane, depending on whether it is complete or incomplete combustion. Complete: C4H10 + 6.502 - 4C02 + 5H20. Incomplete:
C4H10 + (13/2) O2 - 5 H2O + 4 CO2 represents the balanced
My whole thought process: Originally, total # of atoms for each element on reactant and product side. Reactants Products. C- 4 C- 1. H 10 H- 2. O- 2 O- 3. Need to get the # of atoms
1. Write down the chemical equation for the combustion of octane. C8H18 + O2 - CO2 + H2O. 2. Determine the count of each element in the reactant and product side of the equation.
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