How many atoms of hydrogen are there in 18 grams of water?


There are 1.204 x 10^24 atoms of hydrogen present in 18 grams of water. In order to calculate this, it is necessary to compute the number of hydrogen moles present in the sample.

A molecule of water consists of a single atom of oxygen and two atoms of hydrogen. Oxygen has an atomic weight of 15.9994. One mole of oxygen, therefore, has a mass of just under 16 grams. Hydrogen has an atomic weight of 1.0079, and so a mole of hydrogen weighs just over 1 gram. This means that 18 grams of water contains one 16-gram mole of oxygen and two 1-gram moles of hydrogen. The number of particles in a mole is a constant known as Avogadro's number, which has a value of 6.022 x 10^23. Two moles of hydrogen, therefore, is double Avogadro's number.

Q&A Related to "How many atoms of hydrogen are there in 18 grams..."
6.6x1022 per gram of water.
240.00 grams H2O x (1 mole H2O / 18.00 grams H2O) x (2 mole H/ 1
ok you have H20 ---> 2H+ + O-2 Molar mass of H20 2 H at 1.01g each = 2.02g 1 O at 16.00g each = 16.00g total = 18.02 g of H20 141g of H20 / 18.02g of H20 = 7.825 mole you need
In a water molecule, the angle between
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