# How many molecules of oxygen (o2) are present in 16.0 g of o2?

## Answer

O2 is Diatomic and has a molecular weight of 32 amu. To calculate the number of molecules of Oxygen in 16 grams of O2 you'll do the following:16 divided by 32 = .5 molecules of O2. One molecule contains 6.02 x 10 to the 23rd power. Next, take .5 mol. O2 multiplied by 6.022 x 10 to the 23rd power and you'll get 3.01 x 10 to the 23rd power molecule. That means there are 3.01 x 10 to the 23rd molecule of O2 in 16 grams of O2.
Q&A Related to "How many molecules of oxygen (o2) are present..."
 http://www.kentchemistry.com/links/GasLa…. use this. http://answers.yahoo.com/question/index?qid=201111...
 a. number of atoms = mass / molar mass x avagadros number. 21/16x6.02x10. 23. =7.9x10. 23. atoms. b. number of atoms = moles x avagadros number. 0.812x6.02x10. 23. =4.89x10. 23. atoms http://wiki.answers.com/Q/How_many_atoms_of_oxygen...
 This is really a chemistry question, but. 6.02 x 10^23 molecules of O₂ = 32 grams. 0.500 mole of O₂ = 16 grams. Greatest mass: 6.02 x 10^23 molecules of O₂. Μ http://answers.yahoo.com/question/index?qid=201109...
 28.4 divided by 32.0 gives moles of O2. Times that answer by 6.022 x 10^23 to get molecules of O2. Times that answer by 2 to get atoms of O. http://answers.yahoo.com/question/index?qid=200712...
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