How to Measure a Room for Tile?

Answer

To measure a room for tile, measure from one end to the other lengthwise and then one end to the other width wise. Multiply these two measurements to get your total inches and divide by 12 to get your square footage. Figure out how large the tiles you want are; typically 12x12 or 18x18 and divide your square footage by that number (12 or 18). This will give you the number of tiles you need. I normally buy what I need and then an extra 2 or 3 boxes to make up for cutting and cutting errors.
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How to Measure a Room for Tile
Everyone has seen a tiled floor that was laid with no planning: Awkward spacing results in small slivers of tile at the edges of the room. Don't let that happen to you when you choose to tile a room. No complicated mathematical calculations are required;... More »
Difficulty: Moderately Easy
Source: www.ehow.com
First you will have to measure each wall and then take each side and multiply it together and that will give you the square footage and depending on the size of the tile that is how you figure out how many tiles you need.
Q&A Related to "How to Measure a Room for Tile?"
 1. Choose a tile. The size, use and style of the room influence your decision. For example, bathrooms require smaller-scale tile that is resistant to water, whereas a family room http://www.ehow.com/how_6011042_measure-room-tile....
 1 Measure the length and width of the room to be carpeted with a tape measure. Use a calculator to multiply the length of the room by the width to determine the square footage. Break http://www.wikihow.com/Measure-a-Room-for-Carpet-T...
 The correct way to measure for a surface you plan to tile is to multiply width by length. For example if a wall is 10 feet high and 5 feet across, you would multiply 10 x 5 and your http://answers.ask.com/Reference/Other/how_to_meas...
 the easiest way to measure a room is to measure each wall individually for instance if your wall is 3.5 metres long by 2.4 metres high you would times them together to get 8.4 square http://uk.answers.yahoo.com/question/index?qid=200...
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