To Prove Quadrilateral Abcd Is a Parallelogram One Must Justify That?


In order to prove that a quadrilateral is a parallelogram one must be able to justify that both of the pairs of the opposite sides are in fact parallel with each other. However it's also important to note that if only one pair of the opposite sides are congruent and parallel the quadrilateral is still considered to be a parallelogram. It can sometimes be rather tricky and confusing when it comes to proving quadrilaterals are parallelograms, that's why it's important to review the many different aspects of proving this.
Q&A Related to "To Prove Quadrilateral Abcd Is a Parallelogram..."
Either AD is parallel to BC or AB and DC are equal.
Okay, I think I have it, and it was easier than I expected. Without loss of generality, set up one side along the y-axis with the midpoint at the origin. One corner of the quadrilateral
a is the answer. Because vertical angles are = you can prove the opposite sides of the quadrilateral are = to each other. y= 2.6x, and. y+9.1= 4x-3.5. Substitute 2.6x for y getting:
Since all four sides are equal they must be 360/4 = 90 degrees. If a quadrilateral has all four sides equal it is a rhombus. However all four angles being 90 degrees doesn't guarantee
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