What is the percentage of water in hydration in copper (II) sulfate pentahydrate?

Answer

The percentage by mass of water of hydration in copper (II) sulfate pentahydrate is about 36%. It is given by mass of hydrate divided by mass of pentahydrate times 100. That is = (90.076 g/mol / 249.685 g/mol) x 100 = 36.07586 % .
Q&A Related to "What is the percentage of water in hydration..."
Atomic weights: Cu=63.5 S=32 O=16 H=1 H2O=18 CuSO4=159.5 CuSO4*5H2O=250 5H2O=90. 90gH2O/250gCuSO4*5H2O x 100% = 36%
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The percent composition of water in CuSO4 * 5H2O
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29.8g H. 2. O = 1.66 mol H. 2. O. Molar Mass CuSO. 4. * 5H. 2. O = 249.6 g. mol CuSO. 4. * 5H. 2. O --> 5 mol H. 2. O. 249.6 g CuSO. 4. * 5H. 2. O/1 mol CuSO. 4. * 5H. 2. O
http://wiki.answers.com/Q/How_many_grams_of_copper...
Moles CuSO4 . 5H2O = 53 g /249.684 g/mol =0.212 Moles water = 5 x 0.212 =1.06 Mass water = 18.02 g/mol x 1.06 mol =19.1 g 53 - 19.1 = 33.9 g of CuSO4
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