Through the axis of the circular end it is MR. 2. but the middle of the cylinder length wise is (1/2)MR. 2. (1/12)ML. 2.
http://wiki.answers.com/Q/What_is_the_moment_of_in...

The moment of inertia is the rotational analog of mass.It is the inertia of a rigid
http://www.chacha.com/question/whatisthe'moment...

1. Multiply half the mass (M) by the sum of the inner and outer radii of the disk if the cutout is in the center of the disk. Thus, the moment of inertia equals 1/2 (M) (R_out + R_in
http://www.ehow.com/how_12018963_momentsinertiac...

Use torque = I*alpha where I is the moment of inertia and alpha is the angular acceleration. Therefore I = Torque/alpha. To find alpha use rotational kinematic eqn omega = omega0
http://answers.yahoo.com/question/index?qid=200911...
