Topic: Calculus Product Rule
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How to Use the Product Rule in Calculus
In calculus, the product rule can be used to find the derivatives of products of two or more functions in the same equation. From physics to mathematics, the product rule can apply in the classroom as well as for practical applications. By ... Read More »
Source: http://www.ehow.com/how_2178898_use-product-rule-calculus.html
What is the product rule in calculus?
For the derivative of h(x) = f(x)g(x): h'(x) = [f(x)g(x)]' = f'(x)g(x) + f(x)g'(x). Keep em' coming! Read More »
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How to Use the Chain Rule in Calculus
In calculus, the chain rule helps problem solvers calculate and differentiate the composition of one or more functions in the same equation. Whether you are in the classroom or in a real life situation, being able to solve a complex equatio... Read More »
Source: http://www.ehow.com/how_2179156_use-chain-rule-calculus.html
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Calculus Product Rule
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Answers to Other Common Questions
The first thing you have to do is identify whether or not the power rule applies to the equation you are trying to differentiate. Match your equation with the power rule equation (as a definition). Identify the variables in your equation an...
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Calculus is an accumulative course meaning that you should have a solid base for your prerequisites, algebra and Trigonometry. First you need to make sure to know when to use the chain rule. You use the chain rule when you have a function i...
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Source: http://www.ehow.com/how_5726423_identify-chain-rule-calculus.html...
The first thing you have to do is identify whether or not the quotient rule applies to the equation you are trying to differentiate. Match your equation with the quotient rule equation (as a definition). Identify the variables in your equat...
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Source: http://www.ehow.com/how_2178928_use-quotient-rule-calculus.html
If f and g are differentiable functions, then the derivative of the product fg is (fg) '(x) = f(x) g '(x) + g(x) f '(x).
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Identify the variables and associate them with the variables in the equation. Differentiate the first part of the equation...More?
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Take the first term times the derivative of the second term, plus the second times the derivative of the first.
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