Topic: Clausius clapeyron Equation
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What is Clausius-Clapeyron equation?
( klöz·ē·əs kla·pā′rōn i′kwā·zhən ) (thermodynamics) An equation governing phase transitions of a substance, dp/dT = ΔH/(TΔV), in which p is the pressure, T is the temperature at which the phase transition occurs, ΔH is the change in heat c... Read More »
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How to Use Clausius-Clapeyron Equation
The Clausius-Clapeyron equation describes the transition between two phases of matter for a particular substance. This transition can be shown with a pressure-temperature (P-T) diagram. This type of graph shows pressure on the y-axis and te... Read More »
Source: http://www.ehow.com/how_5220919_use-clausiusclapeyron-equation.ht...
What are the significance of Clausius-Clapeyron equation?
It allows for the determination and understanding of the shape and location of liquid-vapor, and solid-vapor phase boundaries. It lets one predict how the vapor pressure vaires with temp and how the boiling temp varies with pressure. GO HUS... Read More »
Source: http://wiki.answers.com/Q/What_are_the_significance_of_Clausius-C...
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Clausius clapeyron Equation
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It stands for euler's number. Its a mathematical constant with the value of approximately 2.72. (Like the value of π(pi) is 3.14, the value of e is 2.72) In the Clausius-Clapeyron equation the "ln"(natural logarithm) is the inverse of "e" e...
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Source: http://wiki.answers.com/Q/What_does_e_stand_for_in_chemistry_in_t...
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Source: http://answers.yahoo.com/question/index?qid=20111114053259AAkWePd
the clausius clapeyron equation is ln(p2/p1)=deltaHvapor/R(1/t1-1/t2)
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Source: http://answers.yahoo.com/question/index?qid=20111125111659AAxYXfP
1. ln(P1/P2) = delt H/R(1/T1-1/T2) ln(400/x) = ((296,000J/mol)/(8.314J/mol*K))*((1/2.59… solve for x. 2. ln (1atm/1.22atm) = ((27,800J/mol)/(8.314J/mol*K))*((1/308K)… solve for x Source(s): chemistry classes
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Source: http://answers.yahoo.com/question/index?qid=20111121195050AAoczFh
ln(P2/P1) = delta Hv/R ( 1/T1 - 1/T2) (1/T1 - 1/T2) = ln(P2/P1) / (delta Hv/R) -1/T2 = ln(P2/P1) / (delta Hv/R) - 1/T1 1/T2 = 1/T1 - ln(P2/P1) / (delta Hv/R) T2 = 1 / { 1/T1 - ln(P2/P1)/ (deltaHv/R)}
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Source: http://answers.yahoo.com/question/index?qid=20090621191744AAlzPrH
the 1n should be clearly written as Ln(P1), means natural log of pressure P1 the equation is Ln(P1) + (H) / (R)(T1) = Ln(P2) + (H) / (R)(T2) P1 is vapor pressure KPa at temp T1 P2 is vapor pressure KPa at temp T2 T1 is temp in K at pressure...
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Source: http://answers.yahoo.com/question/index?qid=20090115084035AAJ3xd9
