Topic: Combination and Permutation Problems
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Answers to Common Questions
How to Convert Combinations to Permutations
Combinations and permutations measure the number of ways items from a set can be grouped. Combinations do not count different orders as different groupings. For example, for the purposes of counting combinations, a selection of chocolate, v... Read More »
Source: http://www.ehow.com/how_8516819_convert-combinations-permutations...
How to Calculate Combinations & Permutations
How many possible winning lottery number combinations are there? How many different combinations can be created for a dial lock? These questions and more can be answered with the statistics tools: combinations and permutations. Combinations... Read More »
Source: http://www.ehow.com/how_4466533_calculate-combinations-permutatio...
How to choose combinations or permutations in a problems?
in combinations, order doesn't matter and its a question of CHOOSING / SELECTING in permutations, order matters, and its a question of ORDERING / ARRANGING to help you, some of the keywords that help to distinguish between the two have been... Read More »
Source: http://answers.yahoo.com/question/index?qid=20090513172755AA95miR
More Common Questions
Answers to Other Common Questions
it is a combination problem, and the formula is nCr = n! / (r! * (n-r)! ),so 11C5 = 11! / (5! * 6!) = 11*10*9*8*7 / (1*2*3*4*5) = 462 --------
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Source: http://answers.yahoo.com/question/index?qid=20091213203554AAKN8rF
These are usually first studied for the purpose of computing probabilities, but they are fundamental mathematics and come often in many different contexts.
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Source: http://wiki.answers.com/Q/What_are_the_applications_of_permutatio...
A permutation is an arrangement of objects in some specific order. Permutations are regarded as ordered elements. A selection in which order is not important is called a combination. Combinations are regarded as sets. For example, if there ...
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Source: http://wiki.answers.com/Q/Difference+between+combination+waste+an...
4 + 6 + 3 = 13 C(13, 4) = 715 715 is total number of combinations that you can make by choosing 4 movies from 13 13total movies - 6 comedies = 7, C(7, 4) is the number of ways you can choose 4 movies without a comedy. 715 - C(7, 4) = 680
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Source: http://answers.yahoo.com/question/index?qid=20120506193104AA5bYHQ
It is a permutation problem. A permutation is where the order of the different arrangements of the parameters are of importance (like the number of ways to arrange 5 books in a shelf). A combination problem is where the order of arrangement...
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Source: http://answers.yahoo.com/question/index?qid=20101218111710AAEjgvG
4 people can be arranged in 4! = 24 ways in one row. 4 people can also be arranged in 4! = 24 ways in two rows. If the order within a row doesnt matter, there are 4C1*3C3 = 4 ways to arrange 4 people into one row of 1 and one row of 3
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Source: http://answers.yahoo.com/question/index?qid=20101104111312AAPjNfT
Those features are all independent. There are therefore: 7 * 3 * 2 = 42 combinations.
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Source: http://answers.yahoo.com/question/index?qid=20080318175838AA1FfC3
