Topic: Discontinuous Function
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What is discontinuity of a function?
continuty: for every point on a line, give me any distance no matter how small, within that distance of the point there is 2 other points ( or more) on the same function discontinuty: does not satisfy that Read More »
Source: http://wiki.answers.com/Q/What_is_discontinuity_of_a_function
What is a discontinueous function
In Math, a Discontinuous Function is a function with a graph that is not connected. Is there anything else we can help you with? Read More »
Source: http://www.chacha.com/question/what-is-a-discontinueous-function
Where is the function is discontinuous.?
Polynomials are always continuous, and the quotient of continuous functions is continuous where the denominator is nonzero. So this function is discontinuous at x = 2. Note: The function simplifies to x + 2 if we assume x is not 2. So this ... Read More »
Source: http://answers.yahoo.com/question/index?qid=20110901173008AAnPf49
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Discontinuous Function
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Answers to Other Common Questions
Probably a mistake. In fact, f(x) is continuous everywhere, including at x=2.
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Source: http://answers.yahoo.com/question/index?qid=20110901171811AAF52QH
The function y=1/x may serve as an example of a function which is discontinuous at the point x=0.
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Source: http://www.chacha.com/question/what-is-a-mathematical-function-th...
If f(x) fails to be continuous because limf(x)x fails to exist (or is infinite), then there is no way to remove jump discontinuity
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Source: http://www.chacha.com/question/what-is-a-practical-use-of-jump-di...
Apple has discontinued the bluetooth headsets for undisclosed reasons.
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Source: http://www.chacha.com/question/why-did-apple-discontinue-the-blue...
Assuming you mean 1/(x + 2) instead of 1/x + 2 on the second line and "1 if x = -2" instead of "1 if x = 2" on the third line, f(2) = 1 lim 1/(x + 2) does not exist x-> -2 Since the f(2) does not equal lim f(x) x-> -2 f(x) is discontinuous ...
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Source: http://answers.yahoo.com/question/index?qid=20120206180837AA7Ihq2
Yes, you are correct: so long as "x" can only be a real number (i.e.: not a complex number), the function is continuous. That is so because the denominator is "x^2 + 16" and it can only equal 0 if x^2 = -16. No real number for "x" can make ...
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Source: http://answers.yahoo.com/question/index?qid=20090130130113AAEEeJ5
