Topic: Double Integrals
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How to Do Double Integrals
In calculus, the integral is a mathematical object that gives the measure of the area under a curve. The basic integral deals with curves of a single independent variable. Double integrals deal with functions of two independent variables an... Read More »
Source: http://www.ehow.com/how_8235646_do-double-integrals.html
How to Find Volume of a Cone by Double Integration
Calculus is an invaluable mathematical tool. It can be used for many different purposes, and is used in most modern technology. One application for calculus is finding the volume of complex multidimensional shapes. One shape that you can us... Read More »
Source: http://www.ehow.com/how_8295738_volume-cone-double-integration.ht...
How calculate the double integral?
First we have to evaluate the inner integral using ILATE method and then evaluate the outer integral Read More »
Source: http://wiki.answers.com/Q/How_calculate_the_double_integral
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Double Integrals
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The integral of a single term of a polynomial, in the form of AxN is (A/N+1) x (N+1). The first integral of 2x is x2 + C. The second integral of 2x is the first integral of x2 + C, which is 1/3x3 + Cx + C.
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Source: http://wiki.answers.com/Q/What_is_the_double_integral_of_2x
∫∫ (x+y)^5 dA; R = { (x,y) -1 ≤ x ≤ 1, 1 ≤ y ≤ 2} Noting that dA = (dy)*(dx), Can be written as either of the following: 1) ( ∫ ( ∫ (x+y)^5 dx [from -1 to 1] ) dy [from 1 to 2] ) OR 2) ( ∫ ( ∫ (x+y)^5 dy [from 1 to 2] ) dx [from -1 to 1] ) ...
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Source: http://answers.yahoo.com/question/index?qid=20120312115218AAwZTdY
[0, π]∫ [0, sinx]∫ (x² - y²) dy dx = [0, π]∫ (x²y - y³/3) |[0, sinx] dx = = [0, π]∫ (x²sinx - (sinx)³/3) dx = [0, π]∫ x²sinx dx – [0, π]∫ (sinx)³/3 dx = J₁ – J₂ J₁ = [0, π]∫ x²sinx dx integrate twice by parts u = x², ......... dv = sinx dx ...
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Source: http://answers.yahoo.com/question/index?qid=20100110173510AAcPHlC
very simple....first integrate the function with respect to x keeping y constant so you get ((X square)/2)*y+(7X square/2)+xy apply the limits for x i,e lower limit is 0 and higher limit is 3 so you get 9/2 * y+21/2+3y then integrate with r...
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Source: http://answers.yahoo.com/question/index?qid=20120207054512AAvsHO7
I think you are trying to solve this inner integral: Integral[y * sin(x^2) , dx, from y^2 to sqrt(pi)] with the outer integral: Integral[ dy, from 0 to pi] Mathematica answer: 1/4 (1 - Cos[\[Pi]^4] + Sqrt[2] \[Pi]^( 5/2) (FresnelS[Sqrt[\[Pi...
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Source: http://answers.yahoo.com/question/index?qid=20111208150824AAMY3T4
let the letter I mean the integral sign IF IT IS SOMETHING LIKE II(a) find the integrand of a and lets call it b then your problem will look like I(b) then just find the integrand of b and call it c so your anser is c but dont forget your c...
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Source: http://answers.yahoo.com/question/index?qid=20090107073003AAoV0ab
