Topic: Examples Of High Order Derivative Equations
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How do you find the following equation in order to find its deriv...
If log is the base10 log and exp(x) = e^x then this gets a little messy. Let's start with the easier problem y = (exp(2ln(x-2)+ln(x)+ln(x^2-1)))/(x-2) We can use the identities exp(rx) = (exp(x))^r , if r is a rational number, exp(ln(x)) = ... Read More »
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What is mathematical correctness on differentiation? verify with ...
http://www4c.wolframalpha.com/Calculate/… Read More »
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How would one approximate this using Euler's method, for example?...
$dt = 0.001; $y=0.01; $dy=0; $ddy=0; for( 1..10000 ){ $ddy = sin($y); $dy += $ddy*$dt;; $y += $dy*$dt;; $t += $dt; print "$t $y\n"; } Read More »
Source: http://www.experts-exchange.com/Q_23615455.htm
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The function y =e^(x) is often derived as the inverse function of y =ln(x) where ln stands for natural log. Their graph is symmetric with each other with respect to the y= x
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if I'm not mistaken, the order of the system is fix, depends on what system is that. For example, the electric system that only involve resistor will always in zero order system, the temperature based system is always in the first order, sp...
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Source: http://answers.yahoo.com/question/index?qid=20091007010337AAisdJt
♦ you are doing it correct so far. Now x(t) = u(t)*e^(2it) +v(t)*e^(-2it); ♣ and take exp(2it) in cos(2t) stead in RHS for a time being; ♦ here solve the system: │ u’(t)*e^(2it) +v’(t)*e^(-2it) = 0; │ u’(t)*(e^(2it))’ +v’(t)*(e^(-2it))’ = e...
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Source: http://answers.yahoo.com/question/index?qid=20060912001731AA0rWrz
Yes you can. You can even get the 2nd derivative implicitly from step 1. Note: when you differentiate next, you have y'', y' , y & x. Replace any y' you see with your equation in step 3 so that your answer will completely be in x & y. PS: I...
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Source: http://answers.yahoo.com/question/index?qid=20070704220939AAZGY1o
yt = φ1yt−1 + φ2yt−2 + bxt + a, ∀t There's no way all these mathematical signs got through, so I suggest taking a look at the source (PDF): http://business.auburn.edu/~hzk0001/lde.pdf Here is the example again: yt = φ1yt−1 + φ2yt−2 + bxt + ...
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Finding a second, third, fourth, or higher derivative is incredibly simple. The second derivative of a function is just the derivative of its first derivative. The third derivative is the derivative of [more…]
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Source: http://www.dummies.com/how-to/education-languages/math/Calculus.h...