Topic: Horizontal Asymtopes
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What is the horizontal and veritcal asymtope?
y = -ln(x) / ln(3/5) vertical asymptote is x = 0 there are no others. you can look up "asymptote." ♣♦ Source(s): http://jpfoss.blogspot.com/2010/09/basic… Read More »
Source: http://answers.yahoo.com/question/index?qid=20120117200611AAmNEaC
How do you fine horizontal asymtopes more?
There is no horizontal asymptote. If the degrees of the numerator and denominator are the same, the horizontal asymptote MORE? Cha Read More »
Source: http://www.chacha.com/question/how-do-you-fine-horizontal-asymtop...
How do you figure out the horizontal asymtope
Answer: Write your function.Take the limit of the function as x approaches ... ...MORE... Read More »
Source: http://www.chacha.com/question/how-do-you-figure-out-the-horizont...
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Horizontal Asymtopes
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Vertical asymptotes will occur when the denominator is 0. You can test this, by seeing that if you plug in values closer and MORE
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Source: http://www.chacha.com/question/how-do-you-find-vertical-and-horiz...
Since lim(x->-infinity){y} = lim(x->infinity){y} = -1, the horizontal asymptote is y = -1. Since the denominator, x^2 - x^4 = x^2(x - 1)(x + 1) is 0 at x = -1, x = 0, and x = 1, these are the equations of the three vertical asymptotes.
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Source: http://answers.yahoo.com/question/index?qid=20100126120849AANF1Ko
With horizontal asymptopes if the polynomial in the denominator has a bigger leading exponent than the polynomial in the MORE
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Source: http://www.chacha.com/question/what-is-the-horizontal-asymtope-of...
y= 2^ (x+3) - 1 ie y + 1 = 2^ (x+3) (y - h) = 2^ (x - k) So h = -1, k = -3 This is a curve of the form Y = 2^X This is assymptotic to the X - axis ie y = 0 In (X, Y) domain is all X and range is Y>0 So the translation of the (X,Y) origin to...
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Source: http://answers.yahoo.com/question/index?qid=20061022163815AArLwZ0
y=5^2x-1 +2 Assuming you mean y=5^(2x-1) +2 y - 2 = 5^(2x - 1) = 5^(2(x - ½)) = 25^(x - ½) (y - h) = 25^(y - k) h = 2; k = ½ Y = 25^X where X = x - ½ and Y = y - 2 For Y = 25^X Domain: All X; Range Y>0 So for y=5^(2x-1) +2 Domain: Still all...
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Source: http://answers.yahoo.com/question/index?qid=20061022163705AAFPoAy
As x goes to infinity (or negative infinity), the highest order term in x for each polynomial will contribute more and more to the sum relative to the other terms until the highest-order term essentially dominates the behavior of the polyno...
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Source: http://answers.yahoo.com/question/index?qid=20081024132542AAV0vpL