Topic: K Probability of Success in a Binomial Trial
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What does the Probability of success in a binomial trial symbol?
In typical notation, "p" is the probability of sucess and "q" is the probability of failure. So q = 1 - p. But for your question: p = p. Read More »
Source: http://wiki.answers.com/Q/What_does_the_Probability_of_success_in...
How do you calculate the probability of k successes for a binomia...
Binomial probability formula is the sum of (nCk)p^k(1-p)n-k For k is less than or = to 3, n = 7, p = 0.3 P = (7C0)(.3^0)(.7)^7 + (7C1)(.3^1)(.7^6) + (7C2)(.3^2)(.7^5) + (7C3)(.3^3)(.7^4) = .0823543 + 0.2470629 + .3176523 + .2268945 = .87396... Read More »
Source: http://answers.yahoo.com/question/index?qid=20111024161548AASmrvd
X is a binomial random variable, where the number of trials is 5 ...
Ok Merlin--- In this problem you're given everything except the probability of success, p The formula for P(x) = nCx *p^x*(1-p) n-x. n = 5, x = 4, and P(x) is 0.12. so 0.12 = 5!/(1!*4!)*p^4*(1-p). 0.12 = 5*p^4(1-p). Now divide both sides by... Read More »
Source: http://answers.yahoo.com/question/index?qid=20111214073741AAcQKEP
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K Probability of Success in a Binomial Trial
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More information is needed to determine the answer to the question. We need to know the probability of success or failure.
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Source: http://wiki.answers.com/Q/What_is_the_probability_of_having_4_con...
0! is defined as 1 so there is not a division by 0 problem. In the case n=x the first part becomes x!/x!0! = 1 Also q^(n-x) = q^0 = 1 So the probability that all of the trials are successes is p^x as you would expect.
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Source: http://answers.yahoo.com/question/index?qid=20120515144636AAKOGfE
The formula for this is P(x) = nCx * p...
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perzngirl - Ooops! Looks like your question was cut off ... try adding Additional Information. Good Luck
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Source: http://answers.yahoo.com/question/index?qid=20120325141028AAiapt2
you seem to be on the right lines probability of success = p ; then probability of failure = ( 1 - p) so P ( three successes followed by 3 failures ) = p^3(1-p)^3 and P (3 failures followed by 3 successes ) = (1-p)^3p^3 =p^3(1-p)^3 of cours...
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Source: http://answers.yahoo.com/question/index?qid=20111128112134AALpoQP
