Topic: Local Maxima Minima
Not finding your answer? Try searching the web for Local Maxima Minima
Answers to Common Questions
How to find local maxima and minima?
Hi, As some people aren't in calculus yet doing derivatives, you can also type the equation into your graphing calculator as Y1 = 2x^3 -3x^2 -36x - 3. Change your window so you can see the hill and valley of the curve. Then use your minimum... Read More »
Source: http://answers.yahoo.com/question/index?qid=20070421193825AAeJ77A
What is a local maxima and local minima of a graph?
Any value of x in the domain of f is called a critical number of f' (also called critical point or critical value) if either MORE Read More »
Source: http://www.chacha.com/question/what-is-a-local-maxima-and-local-m...
How to find local minima, maxima and points of intersection?
The critical points where f'(x)=0 are called stationary points. Start by finding the derivative of your function, set to 0 and solve for x. Since it is just a cubic polynomial, it is easy to differentiate. Read More »
Source: http://www.askmehelpdesk.com/advice/t-74%3C/b%3E%3C/a%3E%3Cbr%3E%...
Featured Content:
Local Maxima Minima
More Common Questions
Answers to Other Common Questions
There's a peak detection function for Matlab, which could be used: http://www.mathworks.com/matlabc... http://terpconnect.umd.edu/~toh/... That detector seems to make the distinction between 'peak' and smoother max/mins that you are inter...
Read More »
Source: http://www.quora.com/What-is-a-good-way-to-identify-local-minima-...
In mathematics, maxima and minima, known collectively as extrema (singular: extremum), are the largest value (maximum) or smallest
Read More »
Source: http://www.chacha.com/question/what-is-a-global-maxima-and-minima
A parabola function has only one minimum OR one maximum. For find this point you should calculate (x = -b/2a) y=-4x^2+8x+7 y = ax^2 + bx + c x = -b/2a = -8 / 2*(-4) = 1 y = =-4(1)^2 + 8(1) + 7 = 11 If a > 0 ==> parabola has minimum, If a < 0 ==> p...
Read More »
Source: http://answers.yahoo.com/question/index?qid=20111119125223AAKrw8s
f(x) = 4 - x + x^2 f ' (x) = - 1 + 2x equate f ' (x) to zero to get critical point -1 + 2x = 0 2x = 1 x = 1/2 This divides the graph into two intervals (- ∞, 1/2 ) , (1/2, ∞) take x = 0 in the interval ( -∞, 1/2 ) f ' (0) = -1 + 0 = -1 < 0,...
Read More »
Source: http://answers.yahoo.com/question/index?qid=20100916172945AAbsBZI
Zero. Minima and maxima occur when f'(x) = 0, or f'(x) doesn't exist. f'(x) = -8e^(-2x) which always exists and is never 0. Similarly, inflection points occur when f''(x) = 0, or f''(x) doesn't exist, and: f''(x) = 16e^(-2x) which exists ev...
Read More »
Source: http://answers.yahoo.com/question/index?qid=20090717051933AA1xPMo
Take the derivative: 6x² - 6x - 36 Find values of x where it equals 0. Devide by 6, x² - x - 6 = 0 (x - 3) (x + 2) = 0 x = 3 x = -2
Read More »
Source: http://answers.yahoo.com/question/index?qid=20080619051048AAHkda0
