Topic: Logarithmic Expressions
Not finding your answer? Try searching the web for Logarithmic Expressions
Answers to Common Questions
How to Calculate Logarithmic Expression
Logarithms may be thought of as the opposites of exponents, just like subtraction is the opposite of addition. An exponent may be described as a number raised to a power. Calculating or solving a logarithmic equation requires a basic unders... Read More »
Source: http://www.ehow.com/how_7503017_calculate-logarithmic-expression....
What is 25 expressed in logarithmic form?
Logarithms appear in all sorts of calculations in engineering and science, business and economics. Before MORE? Read More »
Source: http://www.chacha.com/question/what-is-25-expressed-in-logarithmi...
How to expand this logarithmic expression?
a * log[b](c) = log[b](c^a) log[b](a) + log[b](c) = log[b](a * c) log[b](a) - log[b](c) = log[b](a / c) (1/4) * log[b](16) = log[b](16^(1/4)) = log[b](2) 2 * log[b](5) = log[b](5^2) = log[b](25) log[b](7) = log[b](7) log[b](2) - log[b](25) ... Read More »
Source: http://answers.yahoo.com/question/index?qid=20100125170151AAGAqnD
More Common Questions
Answers to Other Common Questions
Question is unclear due to lack of brackets. Have then to GUESS that question may be :- 7 ln x - (1/3) lny ln x^7 + ln y^(-1/3) ln [ x^7 / y^(1/3) ]
Read More »
Source: http://answers.yahoo.com/question/index?qid=20110924123948AA2a3DA
y = log9(0.6) = log9(3/5) = log9(3) - log9(5) [from logarithm law, logc(a/b) = logc(a) - logc(b)] = log9(9^(1/2)) - log9(5) [logc(a^b) = bloga, and loga(a) = 1] = 1/2 - log9(5) = 1/2 - (log3(5)/log3(9)) [change of base law, loga(b) = logc(b...
Read More »
Source: http://answers.yahoo.com/question/index?qid=20111010214928AAzOXcg
We use the rule: log(ab) = log(a) + log(b). It does not matter what the base of the logarithms are but they must be the same. Hence: log (10T) = log(10) + log(T) which is the sum of logarithms and is the required answer. If you were using l...
Read More »
Source: http://answers.yahoo.com/question/index?qid=20100208080510AALHPAr
ln (a^b) = b*ln(a) ln(a*b) = ln(a) + ln(b) ln(a/b) = ln(a) - ln(b) So let's go and try it: ln ([(x - 3)^4(x^2 + 1)] / (2x + 5)^3)^(1/5) = (1/5) * ln ([(x - 3)^4(x^2 + 1)] / (2x + 5)^3) = (1/5) * ( ln [(x - 3)^4(x^2 + 1)] - ln ((2x + 5)^3) )...
Read More »
Source: http://answers.yahoo.com/question/index?qid=20091018114826AAJ2d4k
Another way to write the log of a quotient is to take the log of the numerator and subtract the log of the denominator.
Read More »
Source: http://www.chacha.com/question/how-do-you-evaluate-a-logarithmic-...
Write the expression as a single logarithm whose coefficient is 1. Where possible, evaluate logarithmic expressions.
Read More »
Source: http://www.chacha.com/question/how-do-i-condense-expressions-into...
log(100*x). When you multiply x by 100 its log goes up by 2.
Read More »
Source: http://www.answerbag.com/q_view/1807078
