Topic: Midpoint Rule
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Why is the midpoint rule more accurate than the trapezoidal rule?
The trapezoidal rule is less accurate than the midpoint rule because the edges of the trapezoids cause some error. Read More »
Source: http://www.chacha.com/question/why-is-the-midpoint-rule-more-accu...
How do I approximate this integral by both midpoint and trapezoid...
1) h = [1-(-1)]/2 =1 sum = 0.1{[ f[a(0)]+2*f[a(1)]+2*f[a(2)]+2*f[a(3)] +2*f[a(4)]+2*f[a(5)]+2*f[a(6)] +2*f[a(7)]+2*f[a(8)]+2*f[a(9)] +f[a(10)]} [1-(-1)]/2=1 0.1[0+2*f[a(1)]+2*f[a(2)]+2*f[a(3)] +2*f[a(4)]+2*f[a(5)]+2*f[a(6)] +2*f[a(7)]+2*f[a... Read More »
Source: http://answers.yahoo.com/question/index?qid=20100117132543AAA63UV
What is the rate of decrease for Simpson's Rule and Midpoint Rule...
You need to add more details for your question since there is not enough info to answer your question. What function do we have? Please indicate that, so there is an answer Good luck! Source(s): Experience Read More »
Source: http://answers.yahoo.com/question/index?qid=20111001163451AAv6wa8
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Midpoint Rule
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There is no definite order--it is not too hard to construct a function where Simpson's rule works better than the others, or where the Trapezoidal Rule works better than the others, or where the Midpoint rule works better than the others. I...
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Source: http://answers.yahoo.com/question/index?qid=20071209200630AADzoCx
With this table, you can't GUESS at the y-value between 1.0 and 1.2 ... we need proper values! 1.0 - 1.2 - 1.4 1.2 is the midpoint of 1.0 and 1.4 ... so, you're right with deltaX = 0.4 Area = 0.4*f(1.2) + 0.4*f(1.6) + .... Area = 0.4*5.2 + ...
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Source: http://answers.yahoo.com/question/index?qid=20090621114615AANoVyt
The integral is 0.25x^4. The question does not specify any limits, so I can't use the midpoint rule.
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Source: http://answers.yahoo.com/question/index?qid=20100304115254AA2gPPI
The bound on the error for the midpoint rule is smaller. See http://www.ltcconline.net/greenl/courses… If the function is concave or convex, the trap rule over or understates the area, while the midpoint rule sort of overstates part of the ...
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Source: http://answers.yahoo.com/question/index?qid=20090622145348AAmyL5U
ln 5 = integral(x=1 to 5, dx/x) ~= f((1+3)/2) * h + f((3+5)/2) * h = (1/2) * 2 + (1/4) * 2 = 3/2 The error is 1.5 - ln5 ~= 0.11, or 6.8%.
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Source: http://answers.yahoo.com/question/index?qid=20111003211307AAokShS
Tsk....3 intervals with total length means stepwidth is 2 / 3---> midpoints are { 1/3, 3/3, 5/3}..compute the function values at these , add together, multiply by the step-width...midpoint rule for approximating an integral trap rule...{ tr...
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Source: http://answers.yahoo.com/question/index?qid=20090112135616AAU872C
