Topic: Proving Trigonometric Identities
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How to prove trigonometric identities?
in order to "prove" a trig identity, you will have to transform one side of the equation into the other side -------------- (1 - cos ϴ) / sin ϴ = csc ϴ - cot ϴ (1 - cos ϴ) / sin ϴ >> divide each term in 1 - cos ϴ by sin ϴ = (1 / sin ϴ) - (c... Read More »
Source: http://answers.yahoo.com/question/index?qid=20120506182405AAy9lhB
How prove these trigonometric identities?
to proove cscϕ/secϕ = (1+cotϕ)/(1+tanϕ) LHS = (1+cotϕ)/(1+tanϕ) where cotϕ=cosϕ/sinϕ and tanϕ = sinϕ/cosϕ = (1+(cosϕ/sinϕ))/(1+(sinϕ/cosϕ)) = ((cosϕ+sinϕ)/sinϕ)/((cosϕ+sinϕ)/cosϕ) = cosϕ/sinϕ wkt cosϕ=1/secϕ and sinϕ=1/cosecϕ = cscϕ/secϕ LH... Read More »
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How to prove these trigonometric identities?
You should be careful how you note your trig functions. What is "sen"? Is it the sinus ("sin")? 1) Can't figure the first one, and I'm not even sure you wrote it well. Even WolframAlpha gives you only discrete values of x where the equality... Read More »
Source: http://answers.yahoo.com/question/index?qid=20120308162517AAkMqJq
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how to prove trigonometric identities tutoring: Academic LifeCharles Henry Turner began his academic prowess.....
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Source: http://www.tutorvista.com/math/proving-trigonometric-identities-l...
... LHS = { cos a / [ 1 - ( sin a / cos a ) ] } + { sin a / [ 1 - ( cos a / sin a ) ] } = [ cos² a / ( cos a - sin a ) ] - [ sin² a / ( cos a - sin a ) ] } = ( cos² a - sin² a ) / ( cos a - sin a ) = ( cos a - sin a )( cos a + sin a ) / ( c...
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Source: http://answers.yahoo.com/question/index?qid=20111030031733AAhTU6k
Think of the Sin(x) graph. It is periodic, with period 2pi. so Sin(x+2pi) = Sin(x) so we already have -sin(x) = sin(-x) to prove. in fact, this is but another identity, that can be seen from considering the graph of Sin(x).
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Source: http://answers.yahoo.com/question/index?qid=20090413181344AAFzQaG
1. 1-cos^2x=sin^2x=1/cosec^2x 2. cos x/(1+sinx) = 1/[(1/cos x)+(sin x/cos x)] = 1/(sec x + tan x) = (sec x - tan x)/(sec x + tan x)(sec x -tan x) = (sec x - tan x)/(sec^2x-tan^2x) = sec x - tan x 3. (1/1-sin x)+(1/1+sin x) = (1+sin x + 1 -s...
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Source: http://answers.yahoo.com/question/index?qid=20080924175828AAyi5aT
In fact, we do not "know that arccos(-x) = π - arccos(x)" since this is the example given for what is to be proved! I find the most direct approach is to use the analytic analogues of the trigonometric functions in the Complex plane derived...
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Source: http://answers.yahoo.com/question/index?qid=20090726160405AAhqlS9
tan@[sin@+cot@cos@]=sec@ tan@[sin@+1/tan@(cos@)]=sec@ tan@[sin@+cos@/tan@]=sec@ tan@(sin@) + tan@(cos@/tan@) = sec@ tan@(sin@) + cos@ = sec@ (sin@/cos@)sin@ + cos @ = sec@ sin^2@/cos@ + cos @ = sec@ 1/cos@ [sin^2@ + cos^2@] = sec@ 1/cos@ [1...
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Source: http://answers.yahoo.com/question/index?qid=20090618163230AAzVOLo
sin(t)/1-cos(t)=1+cos(t)/sin(t) Multiply both sides of the equation by (1-cos(t)) sin(t) = (1 + cos(t))(1 - cos(t)) / sin(t) Multiply both sides by sin(t) sin^2(t) = (1 + cos(t))(1 - cos(t)) Expand terms for right half: sin^2(t) = 1 + cos(t...
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Source: http://answers.yahoo.com/question/index?qid=20090318143420AAvpnDf
